Dielectrics and Polarisation

How insulators respond to electric fields — and why they multiply capacitance.

What is a Dielectric?

A dielectric is an insulating material that, when placed in an electric field, develops electric dipoles throughout its volume. It does not allow charge to flow (unlike a conductor), but it responds to the field by internally reorganising its charge distribution.

In the absence of a field, the positive and negative charge centres in each molecule coincide — no net dipole. When a field is applied, these charges shift slightly: positive charges shift in the direction of \( \vec{E} \), negative charges against it. Each molecule becomes an electric dipole. This process is called polarisation.

Types of Dielectrics

Non-Polar Dielectrics

Molecules with no permanent dipole moment (e.g., \( \text{O}_2 \), \( \text{H}_2 \), \( \text{CO}_2 \)). Dipoles are induced only when a field is applied. The induced dipole moment is proportional to the applied field.

Polar Dielectrics

Molecules with a permanent dipole moment (e.g., \( \text{H}_2\text{O} \), \( \text{HCl} \)). In the absence of a field, the dipoles are randomly oriented due to thermal motion, giving zero net polarisation. An external field partially aligns them — both rotating the existing dipoles and inducing a small additional moment.

Polarisation Vector

The polarisation \( \vec{P} \) is defined as the electric dipole moment per unit volume:

\[ \vec{P} = \frac{\text{net dipole moment}}{\text{volume}} \quad \text{(unit: C/m}^2\text{)} \]

For a linear dielectric, \( \vec{P} \) is proportional to the applied electric field:

\[ \vec{P} = \varepsilon_0 \chi_e \vec{E} \]

where \( \chi_e \) is the electric susceptibility of the dielectric. The dielectric constant (relative permittivity) is related by \( K = \varepsilon_r = 1 + \chi_e \).

Bound Charges and the Reduced Field

The aligned dipoles produce a layer of positive bound charge on one surface of the dielectric slab and negative bound charge on the opposite surface. These bound surface charges set up a field \( \vec{E}_p \) inside the dielectric that opposes the applied field:

\[ E_{\text{inside}} = E_0 - E_p = \frac{E_0}{K} \]

The surface charge density of the bound charges is:

\[ \sigma_b = P = \varepsilon_0 \chi_e E_{\text{inside}} \]
The net effect of inserting a dielectric is to reduce the electric field inside by a factor \( K \). Since \( C = Q/V \) and \( V = Ed \), a smaller \( E \) means a smaller \( V \) for the same \( Q \) — so \( C \) increases by factor \( K \).

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